App-Development-with-Swift-Certified-User App Development with Swift Certified User Exam Questions and Answers

This question belongs to Swift Programming Language , specifically the objectives covering functions , control flow , and default parameter values . The function is declared as func getAgeCategory(_ age: Int = 20) - > Int, which means if no argument is supplied, Swift uses the default value 20. Apple’s Swift documentation explains that you can define a default value for any parameter, and that value is used when the caller omits that argument. Since the code calls getAgeCategory() with no parameter, the function executes using age = 20.

The conditional logic is then evaluated in order:

if age > 64 → false, because 20 is not greater than 64

else if age > 19 → true, because 20 is greater than 19

so the function returns 2

Because Swift’s if / else if control flow stops at the first true condition, the later checks are never reached once age > 19 succeeds. Apple describes Swift as supporting standard control flow including conditional branching, and this example is a direct use of that branching behavior.

Therefore, print(getAgeCategory()) outputs 2 , which corresponds to option B .

This question belongs to View Building with SwiftUI , especially the domain on creating multiple views to implement app logic and sharing values between views. In FirstView, the value typed into the TextField is stored in number, which is a String. When the NavigationLink is tapped, the code passes Int(number) ?? 0 into SecondView. In Swift, converting a string to an integer with Int(...) uses an optional initializer, which means it returns an optional value and will produce nil if the string cannot be converted. The ?? 0 nil-coalescing operator then supplies 0 if conversion fails.

Inside SecondView, the body is:

Color(passedNumber == 3 ? .blue : .red)

This uses the ternary conditional operator. If passedNumber equals 3, the displayed color is blue; otherwise, it is red. Therefore, entering 3 into the TextField causes Int(number) to become 3, which makes the condition passedNumber == 3 true and displays a blue canvas. Any other listed number results in red.

So the correct answer is A. 3 . This matches the SwiftUI pattern of taking user input, converting it to the needed type, passing it into another view, and rendering UI conditionally based on that value.

This question belongs to Swift Programming Language , especially the domains covering control flow , loops , logical operators , and guard . The loop runs through 0.. < max, and since max = 101, the values of num are 0 through 100. Inside the loop, the guard statement keeps only values that satisfy both conditions:

num % 5 == 0 → the number must be divisible by 5

num % 2 != 0 → the number must be odd

So the code counts numbers from 0 to 100 that are odd multiples of 5 . Those values are:

5, 15, 25, 35, 45, 55, 65, 75, 85, 95

That gives a total of 10 numbers. Therefore count becomes 10, and the printed output is:

Total count: 10

The key Swift concept here is that guard ... else { continue } skips any loop iteration that does not meet the required condition. Only matching values reach count += 1. This is a standard use of guard for early exit and of the remainder operator % for divisibility checks. Therefore, the correct answer is B .

age — Variable

birthDate — Constant

socialSecurityNumber — Constant

salary — Variable

currentDepartment — Variable

This question belongs to Swift Programming Language , specifically the objective on demonstrating when to use constants and variables . In Swift, a constant is declared with let and is used for values that should not change after they are set. A variable is declared with var and is used for values that may change over time.

Birth date is a constant because a person’s date of birth does not change. Social security number is also a constant because it is intended to be a fixed identifier for that employee record. By contrast, age is a variable because it changes over time. Salary is a variable because compensation can be adjusted. Current department is also a variable because an employee may transfer to another department.

This matches Swift best practice: use let for fixed data and var for mutable data. So in a human resources record, identifiers that are permanent should be constants, while values that can change during employment should be variables.

This question belongs to Swift Programming Language , specifically the objective on managing data using collection types , including dictionaries and arrays . In the dictionary shown, the emojis are the keys and the text descriptions are the values . Swift provides a keys property on dictionaries that returns a collection containing all dictionary keys. To convert that keys collection into an array, you use the Array(...) initializer. Therefore, the correct code is let emojis = Array(faces.keys). Apple documents both the Dictionary.keys property and the Array type used to store a sequence of values of the same type.

Option B is incorrect because faces.values would return the descriptions like " grinning " , " thinking " , and " happy " , not the emoji keys. Options A and C are incorrect because List is a SwiftUI view type, not the correct collection type for creating an array from dictionary contents. Also, the dictionary interface uses properties like .keys and .values, not method calls like .keys() or .values(). Apple’s dictionary documentation makes clear that keys is a property returning a collection of the dictionary’s keys.

This question belongs to View Building with SwiftUI , especially the domain covering positioning and/or layout a single SwiftUI View with standard Views and modifiers and the foundational structure of a SwiftUI view. In SwiftUI, a custom screen is typically declared as a struct that conforms to the View protocol. Apple’s SwiftUI documentation shows the standard pattern:

struct ScreenView: View {

var body: some View {

Text( " Hello " )

}

}

Here, struct is required because SwiftUI views are commonly defined as structures. View is required after the colon because the type must conform to the View protocol. body is the required computed property that returns the content of the view as some View. Apple documents that every conforming View type must provide a body property that describes its content.

So the completed code is:

import SwiftUI

struct ScreenView: View {

var body: some View {

Text( " Hello " )

}

}

This is the canonical SwiftUI view declaration pattern and is one of the most fundamental concepts in App Development with Swift.

You can treat a NavigationLink like a button, and run some Swift code when it is pressed. — False

NavigationSplitView can be used to do navigation differently on different device sizes. — True

You can put a header on your present View in a NavigationStack using .navigationTitle. — True

If you have a NavigationLink that goes to another View with a NavigationLink, you need to declare a NavigationStack at each level. — False

This question belongs to View Building with SwiftUI , specifically the objective on creating a multi-view app with navigation stacks, links, and sheets . Statement 1 is False because NavigationLink is primarily a navigation control that pushes or presents a destination in a navigation container; Apple documents it as creating a navigation link that presents a destination, not as a general-purpose action control like Button.

Statement 2 is True because NavigationSplitView is designed for adaptive navigation and can present navigation in different ways depending on platform and available space. Apple documents NavigationSplitView as a container for navigation across multiple columns, and this adaptive behavior is exactly why it is used differently across device sizes.

Statement 3 is True because .navigationTitle(...) sets the navigation title for a view shown inside a navigation container. Apple explicitly describes a view’s navigation title as something used to visually display the current navigation state of an interface.

Statement 4 is False because you do not need a separate NavigationStack at every level. Apple describes NavigationStack as the container that manages a stack of views, and NavigationLink pushes additional destinations onto that stack. Nested destinations can keep navigating within the same stack.

This question belongs to View Building with SwiftUI , especially the objective domain on using List views to iterate through collections and displaying model data in SwiftUI. In the code, animals is the data source passed into List(animals) { animal in ... }. That closure iterates through each element of the collection one at a time, and the parameter animal represents the current Animal instance for that row. To show the name of the current animal in the UI, the correct statement is Text(animal.name). SwiftUI’s list documentation explains that each row inside a List must be a SwiftUI View, and a Text view is a standard way to display a string value for each item in the collection.

Option D is therefore correct because it accesses the name property of the current animal object being processed by the List closure. This is the standard SwiftUI pattern when iterating over identifiable model objects: pass the collection into List, receive each item in the closure, and build a row view from that item’s properties. Apple’s SwiftUI tutorials repeatedly use this collection-driven row-building pattern for lists and navigation.

The other options are incorrect for clear reasons. A incorrectly refers to the type name Animal instead of the current instance. B uses Animals with the wrong identifier and an invalid indexing approach. C also treats animal as an index rather than the current element object. Since the closure already gives you the current Animal, you directly access its property with animal.name.

This question belongs to View Building with SwiftUI , specifically stacking views and applying modifiers. A ZStack layers views from back to front, so the first item becomes the background and later items appear on top. To match the screenshot, the black background must be the back layer, so Color.black goes first. The large white circle sits above that, so Circle() followed by .foregroundStyle(.white) comes next. Finally, the red heart image sits on top of the circle, so Image(systemName: " heart " ).resizable() followed by .foregroundStyle(.red).frame(width: 200, height: 200) must be last. SwiftUI’s Image.resizable() allows the symbol image to scale to the frame you apply, and foregroundStyle sets the visible color styling for the shape and symbol.

So the intended structure is:

ZStack {

Color.black

Circle()

.foregroundStyle(.white)

Image(systemName: " heart " ).resizable()

.foregroundStyle(.red)

.frame(width: 200, height: 200)

}

This produces a black background, a white circular shape, and a centered red heart on top, exactly as shown.