PCEP-30-02 PCEP - Certified Entry-Level Python Programmer Questions and Answers

The code snippet that you have sent is trying to print the combined length of two lists, “collection” and “duplicate”. The code is as follows:

collection = [] collection.append(1) collection.insert(0, 2) duplicate = collection duplicate.append(3) print(len(collection) + len(duplicate))

The code starts with creating an empty list called “collection” and appending the number 1 to it. The list now contains [1]. Then, the code inserts the number 2 at the beginning of the list. The list now contains [2, 1]. Then, the code creates a new list called “duplicate” and assigns it the value of “collection”. However, this does not create a copy of the list, but rather a reference to the same list object. Therefore, any changes made to “duplicate” will also affect “collection”, and vice versa. Then, the code appends the number 3 to “duplicate”. The list now contains [2, 1, 3], and so does “collection”. Finally, the code tries to print the sum of the lengths of “collection” and “duplicate”. However, this causes an exception, because the len function expects a single argument, not two. The code does not handle the exception, and therefore outputs nothing.

The expected output of the code is nothing, because the code raises an exception and terminates. Therefore, the correct answer is D. The code raises an exception and outputs nothing.

The code snippet that you have sent is a while loop with an if statement and a print statement inside it. The code is as follows:

while True: if counter < 0: print(““) else: print(”**”)

The code starts with entering a while loop that repeats indefinitely, because the condition “True” is always true. Inside the loop, the code checks if the value of “counter” is less than 0. If yes, it prints a single asterisk () to the screen. If no, it prints three asterisks (**) to the screen. However, the code does not change the value of “counter” inside the loop, so the same condition is checked over and over again. The loop never ends, and the code enters an infinite loop.

The program outputs either one asterisk () or three asterisks (**) to the screen repeatedly, depending on the initial value of “counter”. Therefore, the correct answer is D. The program enters an infinite loop.

One possible way to drag and drop the conditional expressions to obtain a code which outputs * to the screen is:

if pool > 0:

print("*")

elif pool < 0:

print("**")

else:

print("***")

This code uses the if, elif, and else keywords to create a conditional statement that checks the value of the variable pool. Depending on whether the value is greater than, less than, or equal to zero, the code will print a different pattern of asterisks to the screen. The print function is used to display the output. The code is indented to show the blocks of code that belong to each condition. The code will output * if the value of pool is positive, ** if the value of pool is negative, and *** if the value of pool is zero.

You can find more information about the conditional statements and the print function in Python in the following references:

[Python If … Else]

[Python Print Function]

[Python Basic Syntax]

The code snippet that you have sent is a loop that checks if a variable “floor” is less than or equal to 0 and prints a string accordingly. The code is as follows:

floor = 5 while floor > 0: print(“+”) floor = floor - 1

The code starts with assigning the value 5 to the variable “floor”. Then, it enters a while loop that repeats as long as the condition “floor > 0” is true. Inside the loop, the code prints a “+” symbol to the screen, and then subtracts 1 from the value of “floor”. The loop ends when “floor” becomes 0 or negative, and the code exits.

The code outputs five “+” symbols to the screen, one for each iteration of the loop. Therefore, the correct answer is C. five.

The code snippet that you have sent is a conditional statement that checks if a variable “counter” is less than 0, greater than or equal to 42, or neither. The code is as follows:

if counter < 0: print(““) elif counter >= 42: print(”“) else: print(””)

The code starts with checking if the value of “counter” is less than 0. If yes, it prints a single asterisk () to the screen and exits the statement. If no, it checks if the value of “counter” is greater than or equal to 42. If yes, it prints three asterisks () to the screen and exits the statement. If no, it prints two asterisks () to the screen and exits the statement.

The expected output of the code depends on the value of “counter”. If the value of “counter” is 10, as shown in the image, the code will print two asterisks (**) to the screen, because 10 is neither less than 0 nor greater than or equal to 42. Therefore, the correct answer is C. * *

Syntax is the branch of linguistics that studies the structure and rules of sentences in natural languages. Lexis is the vocabulary of a language. Semantics is the study of meaning in language. A dictionary is a collection of words and their definitions, synonyms, pronunciations, etc.